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Clarify key_value_swap's edge case (#10799)

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In compiler design especially, leaving behavior as "undefined" is a _strong_ condition that basically states that all possible integrity is violated; it's the kind of thing that happens when, say, dereferencing a pointer with unknown provenance, and most typically leads to a crash, but can result in all sorts of spectacular errors--thus, "it is undefined" how your program will melt down.

The pure-Lua implementation of `key_value_swap` does not permit UB _per se_ (assuming the implementation of Lua itself is sound), but does deterministically choose the value to which a key is mapped (the last in visitation order wins--since visitation order is arbitrary, _some_ value _will_ be chosen). Most importantly, the program won't do something wildly unexpected.
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Graham Northup 2021-01-29 11:34:00 -05:00 committed by GitHub
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doc/lua_api.txt
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@ -3275,7 +3275,8 @@ Helper functions
* Appends all values in `other_table` to `table` - uses `#table + 1` to
find new indices.
* `table.key_value_swap(t)`: returns a table with keys and values swapped
* If multiple keys in `t` map to the same value, the result is undefined.
* If multiple keys in `t` map to the same value, it is unspecified which
value maps to that key.
* `table.shuffle(table, [from], [to], [random_func])`:
* Shuffles elements `from` to `to` in `table` in place
* `from` defaults to `1`