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1018e1c29c
Fixes #75
47 lines
1.6 KiB
Python
47 lines
1.6 KiB
Python
# ContentDB
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# Copyright (C) 2022 rubenwardy
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#
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU Affero General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU Affero General Public License for more details.
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#
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# You should have received a copy of the GNU Affero General Public License
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# along with this program. If not, see <https://www.gnu.org/licenses/>.
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import urllib.parse as urlparse
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from typing import Optional, Dict, List
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def url_set_query(url: str, params: Dict[str, str]) -> str:
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url_parts = list(urlparse.urlparse(url))
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query = dict(urlparse.parse_qsl(url_parts[4]))
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query.update(params)
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url_parts[4] = urlparse.urlencode(query)
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return urlparse.urlunparse(url_parts)
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def url_get_query(parsed_url: urlparse.ParseResult) -> Dict[str, List[str]]:
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return urlparse.parse_qs(parsed_url.query)
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def clean_youtube_url(url: str) -> Optional[str]:
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parsed = urlparse.urlparse(url)
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print(parsed)
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if (parsed.netloc == "www.youtube.com" or parsed.netloc == "youtube.com") and parsed.path == "/watch":
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print(url_get_query(parsed))
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video_id = url_get_query(parsed).get("v", [None])[0]
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if video_id:
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return url_set_query("https://www.youtube.com/watch", {"v": video_id})
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elif parsed.netloc == "youtu.be":
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return url_set_query("https://www.youtube.com/watch", {"v": parsed.path[1:]})
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return None
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