fmt and lint

src/NetscriptFunctions/Singularity.ts

@@ -6,7 +6,6 @@ import { startWorkerScript } from "../NetscriptWorker";
 import { Augmentation } from "../Augmentation/Augmentation";
 import { Augmentations } from "../Augmentation/Augmentations";
 import { augmentationExists, installAugmentations } from "../Augmentation/AugmentationHelpers";
-import { prestigeAugmentation } from "../Prestige";
 import { AugmentationNames } from "../Augmentation/data/AugmentationNames";
 import { killWorkerScript } from "../Netscript/killWorkerScript";
 import { CONSTANTS } from "../Constants";

src/data/codingcontracttypes.ts

@@ -801,7 +801,7 @@ export const codingContractTypesMetadata: ICodingContractTypeMetadata[] = [
     desc: (data: number[][]): string => {
       return [
         "You are located in the top-left corner of the following grid:\n\n",
-        `  [${data.map(line => "[" + line + "]").join(",\n   ")}]\n\n`,
+        `  [${data.map((line) => "[" + line + "]").join(",\n   ")}]\n\n`,
         "You are trying to find the shortest path to the bottom-right corner of the grid,",
         "but there are obstacles on the grid that you cannot move onto.",
         "These obstacles are denoted by '1', while empty spaces are denoted by 0.\n\n",
@@ -831,8 +831,7 @@ export const codingContractTypesMetadata: ICodingContractTypeMetadata[] = [
       const minPathLength = dstY + dstX; // Math.abs(dstY - srcY) + Math.abs(dstX - srcX)
 
       const grid: number[][] = new Array(height);
-      for(let y = 0; y < height; y++)
-        grid[y] = new Array(width).fill(0);
+      for (let y = 0; y < height; y++) grid[y] = new Array(width).fill(0);
 
       for (let y = 0; y < height; y++) {
         for (let x = 0; x < width; x++) {
@@ -842,9 +841,8 @@ export const codingContractTypesMetadata: ICodingContractTypeMetadata[] = [
           // Generate more obstacles the farther a position is from start and destination.
           // Raw distance factor peaks at 50% at half-way mark. Rescale to 40% max.
           // Obstacle chance range of [15%, 40%] produces ~78% solvable puzzles
-          const distanceFactor = Math.min(y + x, dstY - y + dstX - x) / minPathLength * 0.8;
-          if (Math.random() < Math.max(0.15, distanceFactor))
-            grid[y][x] = 1;
+          const distanceFactor = (Math.min(y + x, dstY - y + dstX - x) / minPathLength) * 0.8;
+          if (Math.random() < Math.max(0.15, distanceFactor)) grid[y][x] = 1;
         }
       }
 
@@ -887,10 +885,11 @@ export const codingContractTypesMetadata: ICodingContractTypeMetadata[] = [
         for (const [yN, xN] of neighbors(y, x)) {
           const d = distance[y][x] + 1;
           if (d < distance[yN][xN]) {
-            if(distance[yN][xN] == Infinity) // Not reached previously
+            if (distance[yN][xN] == Infinity)
+              // Not reached previously
               queue.push([yN, xN], d);
-            else // Found a shorter path
-              queue.changeWeight(([yQ, xQ]) => yQ == yN && xQ == xN, d);
+            // Found a shorter path
+            else queue.changeWeight(([yQ, xQ]) => yQ == yN && xQ == xN, d);
             //prev[yN][xN] = [y, x];
             distance[yN][xN] = d;
           }
@@ -898,27 +897,33 @@ export const codingContractTypesMetadata: ICodingContractTypeMetadata[] = [
       }
 
       // No path at all?
-      if(distance[dstY][dstX] == Infinity)
-        return ans == "";
+      if (distance[dstY][dstX] == Infinity) return ans == "";
 
       // There is a solution, require that the answer path is as short as the shortest
       // path we found
-      if(ans.length > distance[dstY][dstX])
-        return false;
+      if (ans.length > distance[dstY][dstX]) return false;
 
       // Further verify that the answer path is a valid path
       let ansX = 0;
       let ansY = 0;
       for (const direction of ans) {
         switch (direction) {
-          case "U": ansY -= 1; break;
-          case "D": ansY += 1; break;
-          case "L": ansX -= 1; break;
-          case "R": ansX += 1; break;
-          default: return false; // Invalid character
+          case "U":
+            ansY -= 1;
+            break;
+          case "D":
+            ansY += 1;
+            break;
+          case "L":
+            ansX -= 1;
+            break;
+          case "R":
+            ansX += 1;
+            break;
+          default:
+            return false; // Invalid character
         }
-        if(!validPosition(ansY, ansX))
-          return false;
+        if (!validPosition(ansY, ansX)) return false;
       }
 
       // Path was valid, finally verify that the answer path brought us to the end coordinates

src/utils/Heap.ts

@@ -28,16 +28,14 @@ abstract class BinHeap<T> {
 
   /** Get the value of the root-most element of the heap, without changing the heap. */
   public peek(): T | undefined {
-    if(this.data.length == 0)
-      return undefined;
+    if (this.data.length == 0) return undefined;
 
     return this.data[0][1];
   }
 
   /** Remove the root-most element of the heap and return the removed element's value. */
   public pop(): T | undefined {
-    if(this.data.length == 0)
-      return undefined;
+    if (this.data.length == 0) return undefined;
 
     const value = this.data[0][1];
 
@@ -52,9 +50,8 @@ abstract class BinHeap<T> {
   /** Change the weight of an element in the heap. */
   public changeWeight(predicate: (value: T) => boolean, weight: number): void {
     // Find first element with matching value, if any
-    const i = this.data.findIndex(e => predicate(e[1]));
-    if(i == -1)
-      return;
+    const i = this.data.findIndex((e) => predicate(e[1]));
+    if (i == -1) return;
 
     // Update that element's weight
     this.data[i][0] = weight;
@@ -62,10 +59,11 @@ abstract class BinHeap<T> {
     // And re-heapify if needed
     const p = Math.floor((i - 1) / 2);
 
-    if(!this.heapOrderABeforeB(this.data[p][0], this.data[i][0])) // Needs to shift root-wards?
+    if (!this.heapOrderABeforeB(this.data[p][0], this.data[i][0]))
+      // Needs to shift root-wards?
       this.heapifyUp(i);
-    else // Try shifting deeper
-      this.heapifyDown(i);
+    // Try shifting deeper
+    else this.heapifyDown(i);
   }
 
   /** Restore heap condition, starting at index i and traveling towards root. */
@@ -76,8 +74,7 @@ abstract class BinHeap<T> {
       const p = Math.floor((i - 1) / 2);
 
       // Reached heap-ordered state already?
-      if(this.heapOrderABeforeB(this.data[p][0], this.data[i][0]))
-         break;
+      if (this.heapOrderABeforeB(this.data[p][0], this.data[i][0])) break;
 
       // Swap
       const tmp = this.data[p];
@@ -99,14 +96,11 @@ abstract class BinHeap<T> {
       let toSwap = i;
 
       // Find which one of element i and it's children should be closest to root
-      if(l < this.data.length && this.heapOrderABeforeB(this.data[l][0], this.data[toSwap][0]))
-        toSwap = l;
-      if(r < this.data.length && this.heapOrderABeforeB(this.data[r][0], this.data[toSwap][0]))
-        toSwap = r;
+      if (l < this.data.length && this.heapOrderABeforeB(this.data[l][0], this.data[toSwap][0])) toSwap = l;
+      if (r < this.data.length && this.heapOrderABeforeB(this.data[r][0], this.data[toSwap][0])) toSwap = r;
 
       // Already in order?
-      if(i == toSwap)
-        break;
+      if (i == toSwap) break;
 
       // Not in order. Swap child that should be closest to root up to 'i' and repeat
       const tmp = this.data[toSwap];
@@ -124,7 +118,6 @@ abstract class BinHeap<T> {
   protected abstract heapOrderABeforeB(weightA: number, weightB: number): boolean;
 }
 
-
 /** Binary max-heap. */
 export class MaxHeap<T> extends BinHeap<T> {
   heapOrderABeforeB(weightA: number, weightB: number): boolean {