mirror of
https://github.com/bitburner-official/bitburner-src.git
synced 2025-03-27 20:42:28 +01:00
156 lines
3.7 KiB
TypeScript
156 lines
3.7 KiB
TypeScript
export function HammingEncode(data: number): string {
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const enc: Array<number> = [0];
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const data_bits: Array<any> = data.toString(2).split("").reverse();
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data_bits.forEach((e, i, a) => {
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a[i] = parseInt(e);
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});
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let k = data_bits.length;
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/* NOTE: writing the data like this flips the endianness, this is what the
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* original implementation by Hedrauta did so I'm keeping it like it was. */
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for (let i = 1; k > 0; i++) {
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if ((i & (i - 1)) != 0) {
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enc[i] = data_bits[--k];
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} else {
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enc[i] = 0;
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}
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}
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let parity: any = 0;
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/* Figure out the subsection parities */
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for (let i = 0; i < enc.length; i++) {
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if (enc[i]) {
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parity ^= i;
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}
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}
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parity = parity.toString(2).split("").reverse();
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parity.forEach((e: any, i: any, a: any) => {
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a[i] = parseInt(e);
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});
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/* Set the parity bits accordingly */
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for (let i = 0; i < parity.length; i++) {
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enc[2 ** i] = parity[i] ? 1 : 0;
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}
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parity = 0;
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/* Figure out the overall parity for the entire block */
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for (let i = 0; i < enc.length; i++) {
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if (enc[i]) {
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parity++;
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}
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}
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/* Finally set the overall parity bit */
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enc[0] = parity % 2 == 0 ? 0 : 1;
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return enc.join("");
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}
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export function HammingEncodeProperly(data: number): string {
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/* How many bits do we need?
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* n = 2^m
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* k = 2^m - m - 1
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* where k is the number of data bits, m the number
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* of parity bits and n the number of total bits. */
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let m = 1;
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while (2 ** (2 ** m - m - 1) < data) {
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m++;
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}
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const n: number = 2 ** m;
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const k: number = 2 ** m - m - 1;
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const enc: Array<number> = [0];
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const data_bits: Array<any> = data.toString(2).split("").reverse();
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data_bits.forEach((e, i, a) => {
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a[i] = parseInt(e);
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});
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/* Flip endianness as in the original implementation by Hedrauta
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* and write the data back to front
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* XXX why do we do this? */
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for (let i = 1, j = k; i < n; i++) {
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if ((i & (i - 1)) != 0) {
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enc[i] = data_bits[--j] ? data_bits[j] : 0;
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}
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}
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let parity: any = 0;
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/* Figure out the subsection parities */
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for (let i = 0; i < n; i++) {
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if (enc[i]) {
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parity ^= i;
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}
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}
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parity = parity.toString(2).split("").reverse();
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parity.forEach((e: any, i: any, a: any) => {
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a[i] = parseInt(e);
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});
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/* Set the parity bits accordingly */
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for (let i = 0; i < m; i++) {
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enc[2 ** i] = parity[i] ? 1 : 0;
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}
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parity = 0;
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/* Figure out the overall parity for the entire block */
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for (let i = 0; i < n; i++) {
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if (enc[i]) {
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parity++;
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}
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}
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/* Finally set the overall parity bit */
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enc[0] = parity % 2 == 0 ? 0 : 1;
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return enc.join("");
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}
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export function HammingDecode(data: string): number {
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let err = 0;
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const bits: Array<number> = [];
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/* TODO why not just work with an array of digits from the start? */
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for (const i in data.split("")) {
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const bit = parseInt(data[i]);
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bits[i] = bit;
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if (bit) {
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err ^= +i;
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}
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}
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/* If err != 0 then it spells out the index of the bit that was flipped */
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if (err) {
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/* Flip to correct */
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bits[err] = bits[err] ? 0 : 1;
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}
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/* Now we have to read the message, bit 0 is unused (it's the overall parity bit
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* which we don't care about). Each bit at an index that is a power of 2 is
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* a parity bit and not part of the actual message. */
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let ans = "";
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for (let i = 1; i < bits.length; i++) {
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/* i is not a power of two so it's not a parity bit */
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if ((i & (i - 1)) != 0) {
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ans += bits[i];
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}
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}
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/* TODO to avoid ambiguity about endianness why not let the player return the extracted (and corrected)
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* data bits, rather than guessing at how to convert it to a decimal string? */
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return parseInt(ans, 2);
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}
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